Question 21The roots of the equation $2\sqrt{x}+2x^{-\frac{1}{2}}=5$ can be found by solving:$16x^2-92x+1=0$$4x^2-25x+4=0$$4x^2-17x+4=0$$2x^2-21x+2=0$$4x^2-25x-4=0$