Question 2
The equation $$
\begin{aligned} \frac{2x^2}{x-1}-\frac{2x+7}{3} &{}+\frac{4-6x}{x-1}\\ &{}+1=0 \end{aligned}
$$ can be transformed by eliminating fractions to the equation $x^2-5x+4=0.$ The roots of the latter equation are $4$ and $1.$ Then the roots of the first equation are:
\begin{aligned} \frac{2x^2}{x-1}-\frac{2x+7}{3} &{}+\frac{4-6x}{x-1}\\ &{}+1=0 \end{aligned}
$$ can be transformed by eliminating fractions to the equation $x^2-5x+4=0.$ The roots of the latter equation are $4$ and $1.$ Then the roots of the first equation are: