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1953 AMC 12 Question 37

AMC12 · 1953 AMC 12

Question 37

The base of an isosceles triangle is $6$ inches and one of the equal sides is $12$ inches. The radius of the circle through the vertices of the triangle is:
  1. $\dfrac{7\sqrt{15}}5$
  2. $4\sqrt3$
  3. $3\sqrt5$
  4. $6\sqrt3$
  5. none of these