Question 47In the set of equations $z^x=y^{2x},$ $2^z=2\cdot4^x,$ $x+y+z=16,$ the integral roots in the order $x,$ $y,$ $z$ are:$3,$ $4,$ $9$$9,$ $-5,$ $12$$12,$ $-5,$ $9$$4,$ $3,$ $9$$4,$ $9,$ $3$