1952 AMC 12 Question 39
AMC12 · 1952 AMC 12
If the perimeter of a rectangle is $p$ and its diagonal is $d,$ the difference between the length and width of the rectangle is:
$\dfrac{\sqrt{8d^2-p^2}}2$
$\dfrac{\sqrt{8d^2+p^2}}2$
$\dfrac{\sqrt{6d^2-p^2}}2$
$\dfrac{\sqrt{6d^2+p^2}}2$
$\dfrac{\sqrt{8d^2-p^2}}4$