1952 AMC 12 Question 35
AMC12 · 1952 AMC 12
With a rational denominator, the expression $\dfrac{\sqrt2}{\sqrt2+\sqrt3-\sqrt5}$ is equivalent to:
$\dfrac{3+\sqrt6+\sqrt{15}}6$
$\dfrac{\sqrt6-2+\sqrt{10}}6$
$\dfrac{2+\sqrt6+\sqrt{10}}{10}$
$\dfrac{2+\sqrt6-\sqrt{10}}6$
None of these