Question 34The price of an article was increased $p\%.$ Later the new price was decreased $p\%.$ If the last price was one dollar, the original price was:$\dfrac{1-p^2}{200}$$\dfrac{\sqrt{1-p^2}}{100}$One dollar$1-\dfrac{p^2}{10{,}000-p^2}$$\dfrac{10{,}000}{10{,}000-p^2}$