Question 22On hypotenuse $AB$ of a right triangle $ABC$ a second right triangle $ABD$ is constructed with hypotenuse $AB.$ If $BC=1,$ $AC=b,$ and $AD=2,$ then $BD$ equals:$\sqrt{b^2+1}$$\sqrt{b^2-3}$$\sqrt{b^2+1}+2$$b^2+5$$\sqrt{b^2+3}$