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Hanoi Open Mathematics Competition 2011 Junior Question 11

HOMC · Hanoi Open Mathematics Competition 2011 Junior

Question 11

Given a quadrilateral \(ABCD\) with \(AB=BC=3\text{ cm}\), \(CD=4\text{ cm}\), \(DA=8\text{ cm}\), and \(\angle DAB+\angle ABC=180^\circ\), calculate its area.

Editorial convention: \(ABCD\) is the ordinary simple convex quadrilateral with vertices in that order.