Question 15In the solution to this number puzzle, whenever there are three numbers in a straight line, the middle number is the sum of the other two. What is the value of $x$? $\frac12(a+b+c)$$\frac12(b-a-c)$$\frac12(a+b-c)$$\frac12(a-b+c)$$\frac12(b+c-a)$