Câu hỏi 11Tính $A=\frac1{1+2}+\frac1{1+2+3}+\frac1{1+2+3+4}+\cdots+\frac1{1+2+\cdots+50}$.$\frac{40}{51}$$\frac{49}{51}$$\frac{49}{102}$$\frac{49}{50}$