Question 25
$40=2\times2\times2\times5$ is a positive divisor of $1440$ that is a product of $4$ prime numbers.
$48=2\times2\times2\times2\times3$ is a positive divisor of $1440$ that is a product of $5$ prime numbers.
Find the sum of all the positive divisors of $1440$ that are the products of an odd number of prime numbers.
$48=2\times2\times2\times2\times3$ is a positive divisor of $1440$ that is a product of $5$ prime numbers.
Find the sum of all the positive divisors of $1440$ that are the products of an odd number of prime numbers.