Question 5Given that $\cos\alpha=12/13$, where $0^\circ\le\alpha\le 90^\circ$, and that $\tan\beta=3/4$, where $180^\circ\le\beta\le 270^\circ$. Find $\sin(\beta-\alpha)$.$-16/65$$16/65$$-56/65$$56/65$$33/65$