Question 34
Suppose that the two roots of the equation
$$\frac1{x^2-10x-29}+\frac1{x^2-10x-45}-\frac2{x^2-10x-69}=0$$
are $\alpha$ and $\beta$. Find $\alpha+\beta$.
$$\frac1{x^2-10x-29}+\frac1{x^2-10x-45}-\frac2{x^2-10x-69}=0$$
are $\alpha$ and $\beta$. Find $\alpha+\beta$.