Question 9The value of $$\frac1{3+1}+\frac2{3^2+1}+\frac4{3^4+1}+\frac8{3^8+1}+\cdots+\frac{2^{2006}}{3^{2^{2006}}+1}$$ is:$\frac12$$\frac12-\frac{2^{2005}}{3^{2^{2005}}-1}$$\frac12-\frac{2^{2006}}{3^{2^{2006}}-1}$$\frac12-\frac{2^{2007}}{3^{2^{2007}}-1}$None of the above