Question 94
Solve in the real numbers the inequality:
$$
\frac{(x+2)^4}{x^3} - \frac{(x+2)^2}{2x} \geq -\frac{x}{16}.
$$
$$
\frac{(x+2)^4}{x^3} - \frac{(x+2)^2}{2x} \geq -\frac{x}{16}.
$$
Math Olympiad Vault · MathNet 2020 — Math Olympiad Vault — Part 03