Question 143
A square sheet of paper lying on the table is divided into $8 \times 8 = 64$ equal squares. These squares are numbered from **a1** to **h8** as on a chess board (see fig. 1). We now start folding, in such a way that square **a1** always stays in the same spot on the table. First we fold along the horizontal midline (fig. 1). This will cause square **a8** to fold on top of square **a1**. Then we fold along the vertical midline (fig. 2). Next, we fold along the new horizontal midline (fig. 3), et cetera. After folding six times, we have a small package of paper in front of us (fig. 7) that we can consider as a stack of 64 square pieces of paper.
fig. 1
fig. 2
fig. 3
...
fig. 7
The squares in this stack are numbered from bottom to top from 1 to 64.
So square **a1** gets number 1.
Which number does square **f6** get?
fig. 1
fig. 2
fig. 3
...
fig. 7
The squares in this stack are numbered from bottom to top from 1 to 64.
So square **a1** gets number 1.
Which number does square **f6** get?