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1990 AIME Question 4

AIME · 1990 AIME

Question 4

Find the positive solution to $$
\begin{aligned}&\frac1{x^2-10x-29}\\&\quad+\frac1{x^2-10x-45}\\&\quad-\frac2{x^2-10x-69}=0.\end{aligned}
$$