1987 AIME Question 6

Rectangle $ABCD$ is divided into four parts of equal area by five segments as shown, where $XY=YB+BC+CZ,$ $YB+BC+CZ=ZW,$ $ZW=WD+DA+AX,$ and $PQ\parallel AB.$ Find $AB$ (in cm) if $BC=19$ cm and $PQ=87$ cm.