Question 12
Given that
$$\frac{(a-b)(b-c)(c-a)}{(a+b)(b+c)(c+a)}=\frac1{2021},$$
find the value of $\frac a{a+b}+\frac b{b+c}+\frac c{c+a}$.
$$\frac{(a-b)(b-c)(c-a)}{(a+b)(b+c)(c+a)}=\frac1{2021},$$
find the value of $\frac a{a+b}+\frac b{b+c}+\frac c{c+a}$.