Question 3
Let $ABCD$ be a parallelogram of area $240$ $\mathrm{cm}^2$. $E$ is the midpoint of $AD$ and $H$ is the midpoint of $AB$. $G$ is a point on $BC$ such that $BG=2GC$ and $F$ is a point on $CD$ such that $DF=3FC$. $K$ is a point on $AC$ such that the area of triangle $EKF$ is $33$ $\mathrm{cm}^2$. Find the area, in $\mathrm{cm}^2$, of triangle $HKG$.
Answer: ______ $\mathrm{cm}^2$
Answer: ______ $\mathrm{cm}^2$