Question 11
$ABCD$ is a parallelogram. $E$ is a point on the segment $AB$ such that $\frac{AE}{EB}=\frac14$. $F$ is a point on the segment $DC$, $AF$ and $DE$ intersect at $G$, while $CE$ and $BF$ intersect at $H$. If the area of $ABCD$ is $1$ cm$^2$ and the area of triangle $BHC$ is $\frac18$ cm$^2$, find the area, in cm$^2$, of triangle $ADG$.
