Question 139
The positive real numbers $\alpha, \beta, \gamma, \delta$ satisfy the equality:
$$
\alpha + \beta\gamma + \gamma\delta + \delta\beta + \frac{1}{\alpha\beta^2\gamma^2\delta^2} = 18.
$$
Find the maximal possible value of $\alpha$.
$$
\alpha + \beta\gamma + \gamma\delta + \delta\beta + \frac{1}{\alpha\beta^2\gamma^2\delta^2} = 18.
$$
Find the maximal possible value of $\alpha$.