Question 72
Let $x, y, z$ be strictly positive real numbers such that
$$
x+\frac{y}{z}=y+\frac{z}{x}=z+\frac{x}{y}=2
$$
Determine all possible values that the number $x+y+z$ can take.
$$
x+\frac{y}{z}=y+\frac{z}{x}=z+\frac{x}{y}=2
$$
Determine all possible values that the number $x+y+z$ can take.