Question 162
As shown in the figure, points $K$ and $L$ are in the interior of a triangle $ABC$, point $D$ lies on the side $AB$. It is known that points $B$, $K$, $L$, $C$ are concyclic, and $\angle AKD = \angle BCK$, $\angle ALD = \angle BCL$. Prove that $AK = AL$.
