Question 52
Let $ABC$ be an isosceles triangle with $AB = AC$. The altitude from $A$ has length $15$, while the altitude from $B$ has length $24$. What is the area of $ABC$?
(A) $180$
(B) $300$
(C) $240 \sqrt{2}$
(D) $200 \sqrt{3}$
(E) $320$
(A) $180$
(B) $300$
(C) $240 \sqrt{2}$
(D) $200 \sqrt{3}$
(E) $320$