Question 140
$ABCD$ is a convex quadrilateral with $\angle ABC = \angle BCD$. The lines $AD$ and $BC$ intersect at $P$, and the line passing through $P$ and parallel to $AB$ intersects the line $BD$ at $T$. Show that $\angle ACB = \angle PCT$.
Math Olympiad Vault · MathNet 2022-part-05 — 197 problems (EN–VI)