Question 33
Let $x$, $y$, $z$ be real numbers satisfying
$$
\begin{aligned}
2x + y + 4xy + 6xz &= -6 \\
y + 2z + 2xy + 6yz &= 4 \\
x - z + 2xz - 4yz &= -3
\end{aligned}
$$
Find $x^{2} + y^{2} + z^{2}$.
$$
\begin{aligned}
2x + y + 4xy + 6xz &= -6 \\
y + 2z + 2xy + 6yz &= 4 \\
x - z + 2xz - 4yz &= -3
\end{aligned}
$$
Find $x^{2} + y^{2} + z^{2}$.