Question 19In the figure, $\angle A=\angle BEF=\angle EBC=\angle ECD=90^\circ$, $\angle ABF=30^\circ$, $\angle BFE=45^\circ$, $\angle ECB=60^\circ$, and $AB=2CD$. Find $\tan\angle CDE$. $\frac{4\sqrt2}5$$\frac{4\sqrt2}3$$\frac{2\sqrt3}3$$\frac{2\sqrt5}3$$\frac{4\sqrt5}5$