Question 30
Given is a triangle with real side lengths $a$, $b$, $c$ and real area $A$. Prove that
$$ 3a^2 + 3b^2 - c^2 \ge 4\sqrt{3}A. $$
$$ 3a^2 + 3b^2 - c^2 \ge 4\sqrt{3}A. $$
MathNet 2021 — Part 02 Question 30
Math Olympiad Vault · MathNet 2021 — Part 02