Question 9$ABC$ is isosceles at $A , D \in BC , BC = 3 BD$. $CE \perp AD$ at $E \in AD$, and $\angle AEB = 128 ^{\circ}$. Find $\angle BAC$. $52 ^{\circ}$$64 ^{\circ}$$70 ^{\circ}$$76 ^{\circ}$$80 ^{\circ}$