Question 6$A = \frac{\sqrt{x} + 1}{\sqrt{x} + 2} - \frac{\sqrt{x} - 2}{\sqrt{x} - 1} - 3 \frac{\sqrt{x}}{x + \sqrt{x} - 2}$. Choose the $x$ interval satisfying $- \frac{1}{3} \lt A \lt - \frac{1}{4}$.$49 \lt x \lt 100$$1 \lt x \lt 4$$5 \lt x \lt 8$$121 \lt x \lt 130$$35 \lt x \lt 48$