Question 9Traveling at $40 \frac{\,\mathrm{km}}{h}$ arrives $1$ minute late; $45 \frac{\,\mathrm{km}}{h}$ arrives $1$ minute early. Find the distance.$72 \,\mathrm{km}$$48 \,\mathrm{km}$$24 \,\mathrm{km}$$18 \,\mathrm{km}$$12 \,\mathrm{km}$