VTMO 2019 — Grade 8 — semifinal Question 12

Question 12

$ABC$ is isosceles at $A , O$ inside, $OA = 3 \,\mathrm{cm} , OB = OC = 2 \,\mathrm{cm}$, and distance from $O$ to $AB = 1 \,\mathrm{cm}$. Find the distance from $O$ to $BC$.

$\frac{2 \sqrt{6} + 1}{3}$
$\frac{\sqrt{6} - 1}{3}$
$\frac{2 \sqrt{6} - 1}{3}$
$\frac{\sqrt{6} - 1}{2}$
$\frac{\sqrt{6} + 1}{2}$