Question 5The quiz scores of a class with $k > 12$ students have a mean of $8.$ The mean of a collection of $12$ of these quiz scores is $14.$ What is the mean of the remaining quiz scores in terms of $k?$$\dfrac{14-8}{k-12}$$\dfrac{8k-168}{k-12}$$\dfrac{14}{12} - \dfrac{8}{k}$$\dfrac{14(k-12)}{k^2}$$\dfrac{14(k-12)}{8k}$