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2020 AMC 10B Question 15

AMC10 · 2020 AMC 10B

Question 15

Steve wrote the digits $1,$ $2,$ $3,$ $4,$ and $5$ in order repeatedly from left to right, forming a list of $10{,}000$ digits, beginning $123451234512\ldots$ He then erased every third digit from his list (that is, the $3$rd, $6$th, $9$th, $\ldots$ digits from the left), then erased every fourth digit from the resulting list (that is, the $4$th, $8$th, $12$th, $\ldots$ digits from the left in what remained), and then erased every fifth digit from what remained at that point. What is the sum of the three digits that were then in positions $2019,$ $2020,$ and $2021?$
  1. $7$
  2. $9$
  3. $10$
  4. $11$
  5. $12$