Question 7
(RUS) Let $ABCDEF$ be a convex hexagon such that $AB=BC$, $CD=DE$, $EF=FA$. Prove that
$$\frac{BC}{BE}+\frac{DE}{DA}+\frac{FA}{FC}\ge\frac32.$$
When does equality occur?
$$\frac{BC}{BE}+\frac{DE}{DA}+\frac{FA}{FC}\ge\frac32.$$
When does equality occur?