Question 5
(SPA 4) In the triangle $ABC$, with $\angle A=60^\circ$, a parallel $IF$ to $AC$ is drawn through the incenter $I$ of the triangle, where $F$ lies on the side $AB$. The point $P$ on the side $BC$ is such that $3BP=BC$. Show that $\angle BFP=\angle B/2$.