Question 39
(POL 4) Show that the triangle whose angles satisfy the equality
$$\frac{\sin^2A+\sin^2B+\sin^2C}{\cos^2A+\cos^2B+\cos^2C}=2$$
is a right-angled triangle.
$$\frac{\sin^2A+\sin^2B+\sin^2C}{\cos^2A+\cos^2B+\cos^2C}=2$$
is a right-angled triangle.