Question 37
(POL 2) Prove that for arbitrary positive numbers the following inequality holds:
$$\frac1a+\frac1b+\frac1c\le\frac{a^8+b^8+c^8}{a^3b^3c^3}.$$
$$\frac1a+\frac1b+\frac1c\le\frac{a^8+b^8+c^8}{a^3b^3c^3}.$$
IMO Shortlist · IMO 1967 - Longlist Problems