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IMAS 2016/2017 Junior Division Round 2 Question 14

IMAS · IMAS 2016/2017 Junior Division Round 2

Question 14

In $\triangle ABC$, point $G$ is the midpoint of segment $BC$, $BE\perp AC$, $CF\perp AB$ and lines $BE$ and $CF$ intersects at point $H$. If $\angle EGF=90^\circ$, prove that $AH=BC$.

Question illustration