Question 16
Let $ABCDE$ be a convex pentagon such that
$$\angle BAC=\angle CAD=\angle DAE\quad\text{and}\quad\angle ABC=\angle ACD=\angle ADE.$$
The diagonals $BD$ and $CE$ meet at $P$. Prove that the line $AP$ bisects the side $CD$.
$$\angle BAC=\angle CAD=\angle DAE\quad\text{and}\quad\angle ABC=\angle ACD=\angle ADE.$$
The diagonals $BD$ and $CE$ meet at $P$. Prove that the line $AP$ bisects the side $CD$.