Question 9The area of $\triangle EBD$ is one third of the area of the $3$-$4$-$5$ triangle $ABC.$ Segment $DE$ is perpendicular to segment $AB.$ What is $BD?$ $\dfrac{4}{3} $$\sqrt{5} $$\dfrac{9}{4} $$\dfrac{4\sqrt{3}}{3} $$\dfrac{5}{2} $
