Question 126
Solve in the positive real numbers the system:
$$
\begin{cases} \frac{xyz+1}{x+1} = \frac{yzw+1}{y+1} = \frac{zwx+1}{z+1} = \frac{wxy+1}{w+1} \\ x+y+z+w=48 \end{cases} .$$
$$
\begin{cases} \frac{xyz+1}{x+1} = \frac{yzw+1}{y+1} = \frac{zwx+1}{z+1} = \frac{wxy+1}{w+1} \\ x+y+z+w=48 \end{cases} .$$