Question 5
In the real numbers, solve the system of equations
$$
\sqrt{\sqrt{x} + 2} = y - 2,
$$
$$
\sqrt{\sqrt{y} + 2} = x - 2.
$$
$$
\sqrt{\sqrt{x} + 2} = y - 2,
$$
$$
\sqrt{\sqrt{y} + 2} = x - 2.
$$
MathNet 2023-part-02 — 191 problems (EN–VI) Question 5
Math Olympiad Vault · MathNet 2023-part-02 — 191 problems (EN–VI)