Question 175
Given that
$$
(10!)^3 = \overline{47\ 784\ 725\ 83a\ b72\ 000\ 000},
$$
determine the digits $a$ and $b$.
$$
(10!)^3 = \overline{47\ 784\ 725\ 83a\ b72\ 000\ 000},
$$
determine the digits $a$ and $b$.
Math Olympiad Vault · MathNet 2023-part-05 — 191 problems (EN–VI)