Question 79
Find the real solutions of the equation
$$
\frac{4x - 1}{x^2 - 2x + 2} + \frac{4x + 7}{x^2 + 2x + 2} = \frac{4(2x + 3)}{x^2 + 2}.
$$
$$
\frac{4x - 1}{x^2 - 2x + 2} + \frac{4x + 7}{x^2 + 2x + 2} = \frac{4(2x + 3)}{x^2 + 2}.
$$
MathNet 2023-part-05 — 191 problems (EN–VI) Question 79
Math Olympiad Vault · MathNet 2023-part-05 — 191 problems (EN–VI)