Question 88
Let $m$, $n$ be positive integers. Prove that
$$
\lfloor n\sqrt{2} \rfloor \cdot \lfloor m\sqrt{7} \rfloor \lt \lfloor mn\sqrt{14} \rfloor.
$$
$$
\lfloor n\sqrt{2} \rfloor \cdot \lfloor m\sqrt{7} \rfloor \lt \lfloor mn\sqrt{14} \rfloor.
$$