Skip to content / Đến nội dung
ThichHocToan.com

2004 AMC 10B Question 18

AMC10 · 2004 AMC 10B

Question 18

In right triangle $\triangle ACE,$ we have $AC = 12,$ $CE = 16,$ and $EA = 20.$ Points $B,$ $D,$ and $F$ are located on $AC,$ $CE,$ and $EA,$ respectively, so that $AB = 3,$ $CD = 4,$ and $EF = 5.$ What is the ratio of the area of $\triangle BDF$ to that of $\triangle ACE?$

Question illustration
  1. $\dfrac{1}{4}$
  2. $\dfrac{9}{25}$
  3. $\dfrac{3}{8}$
  4. $\dfrac{11}{25}$
  5. $\dfrac{7}{16}$