Question 140
Let $x$, $y$, $z$, and $u$ be real numbers satisfying the equation
$$
\frac{x-y}{x+y}+\frac{y-z}{y+z}+\frac{z-u}{z+u}+\frac{u-x}{u+x}=0
$$
$$
\frac{x-y}{x+y}+\frac{y-z}{y+z}+\frac{z-u}{z+u}+\frac{u-x}{u+x}=0
$$
Math Olympiad Vault · MathNet 2026 — Part 09